The durations in seconds of their first three flights can be represented by consecutive odd integers, such that the product of the first and third was equal to 4 led than five times the second. Find the durations of their first three flights.

Answer:3 sec, 5 sec and 7 sec.Step-by-step explanation:The first important detail is ''consecutive odd integers'', which can be express as: [tex]x; (x+2); (x+4)[/tex]Then, we apply this definitions to the conventional language to convert it to math language:The product of the first and third: [tex]x(x+4)[/tex]4 less than five times the second: [tex]5(x+2) - 4[/tex]So, the expression would be [tex]x(x+4) = 5(x+2) -4[/tex]If we solve this equation, will result: [tex]x^{2}-x-6=0[/tex]; which is an second grade equation.To solve it, we need to find two number that their multiplication results in 6, but their subtract results in 1. Being those numbers, 3 and 2.[tex](x-3)(x+2)=0\\[/tex]So, results are [tex]x=3; x=-2\\[/tex]But, time cannot be negative, so, we only take the first value.If we substituted in the initial expression of the odd integers, we will have:[tex]3; (3+2); (3+4)[/tex] Hence, the numbers are 3, 5 and 7.