Find the X intercept and the Y intercept of the graph of the equation. 9/8x+8y=18

Answer:[tex]\large\boxed{x-intercept=16\to(16,\ 0)}\\\boxed{y-intercept=\dfrac{9}{4}\to\left(0,\ \dfrac{9}{4}\right)}[/tex]Step-by-step explanation:[tex]\dfrac{9}{8}x+8y=18\\\\x-intercept\ \text{is for}\ y=0:\\\\\dfrac{9}{8}x+8(0)=18\\\\\dfrac{9}{8}x+0=18\\\\\dfrac{9}{8}x=18\qquad\text{multiply both sides by}\ \dfrac{8}{9}\\\\\dfrac{8\!\!\!\!\diagup^1}{9\!\!\!\!\diagup_1}\cdot\dfrac{9\!\!\!\!\diagup^1}{8\!\!\!\!\diagup_1}x=\dfrac{8}{9\!\!\!\!\diagup_1}\cdot18\!\!\!\!\!\diagup^2\\\\x=16\\\\y-intercept\ \text{is for}\ x=0:\\\\\dfrac{9}{8}(0)+8y=18\\\\0+8y=18\\\\8y=18\qquad\text{divide both sides by 8}\\\\y=\dfrac{18}{8}\\\\y=\dfrac{9}{4}[/tex]