Can somebody help me with the Math's questions on Pythagoras Theorem? Thanks

Answer:Part a) [tex]AB=17\ m[/tex]Part b) [tex]AC=20.8\ m[/tex]Step-by-step explanation:see the attached figure with letters to better understand the problemPart a) Find the length ABApplying the Pythagoras Theorem in the right triangle ABH[tex]AB^2=AH^2+HB^2[/tex]whereAB is the hypotenuse (the greater side)AH and HB are the legs of the right trianglewe have[tex]AH=FG=8\ m[/tex][tex]HB=GB-ED=26-11=15\ m[/tex]substitute the values[tex]AB^2=8^2+15^2[/tex][tex]AB^2=289[/tex][tex]AB=17\ m[/tex]Part a) Find the length ACApplying the Pythagoras Theorem in the right triangle ABC[tex]AC^2=AB^2+BC^2[/tex]whereAC is the hypotenuse (the greater side)AB and BC are the legs of the right trianglewe have[tex]BC=12\ m[/tex][tex]AB=17\ m[/tex]substitute[tex]AC^2=17^2+12^2[/tex][tex]AC^2=433[/tex][tex]AC=20.8\ m[/tex]